Difference between revisions of "Kerr - June 29, 2016"
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From the math that I understand up until this point, with a maximum light when the polarizers are parallel, we have around 540 uW of power. | From the math that I understand up until this point, with a maximum light when the polarizers are parallel, we have around 540 uW of power. | ||
| − | if &Delta p = 540 uW * sin<sup>2</sup> &theta .... then .1 degrees of rotation corresponds to around .0040 uW of change in power which we can measure. | + | |
| + | |||
| + | if Δ p = 540 uW * sin<sup>2</sup> θ .... | ||
| + | then .1 degrees of rotation corresponds to around .0040 uW of change in power which we can measure. | ||
There must be something we are missing when it comes to the magnetic field and the Kerr effect itself .... Or our setup currently doesn't measure the Kerr effect. | There must be something we are missing when it comes to the magnetic field and the Kerr effect itself .... Or our setup currently doesn't measure the Kerr effect. | ||
Revision as of 09:25, 29 June 2016
From the math that I understand up until this point, with a maximum light when the polarizers are parallel, we have around 540 uW of power.
if Δ p = 540 uW * sin2 θ ....
then .1 degrees of rotation corresponds to around .0040 uW of change in power which we can measure.
There must be something we are missing when it comes to the magnetic field and the Kerr effect itself .... Or our setup currently doesn't measure the Kerr effect.